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Jag har både en Mitsubishi Solid 25 och en Qlima SC-JA2519 och tycker de är likvärdiga i värmekapacitet, Solid är ett par år äldre än Qliman men har bytt innedel två gånger och nu börjar något lager klicka i den tredje innerdelen när man kör brasläget och grejorna inte är varma inuti. Lite tystare än Qliman är den dock.
Yes, it is possible to estimate the heat output of an air source heat pump by measuring the inlet and outlet air temperatures of the indoor unit and knowing the airflow rate. The basic formula to calculate heat output is:Heat Output (Q) = Airflow (Qs) x Specific Heat of Air (Cp) x Temperature Difference (ΔT)Where:- Heat Output (Q) is the heat energy produced by the heat pump in watts (W) or BTUs per hour (BTU/hr).- Airflow (Qs) is the airflow rate in cubic meters per second (m³/s) or cubic feet per minute (CFM).- Specific Heat of Air (Cp) is the specific heat capacity of air, which is typically around 0.24 BTU/(lb·°F) or 1.006 kJ/(kg·°C) for dry air at around room temperature.- Temperature Difference (ΔT) is the temperature difference between the inlet and outlet air in degrees Fahrenheit (°F) or degrees Celsius (°C).Keep in mind that this is a simplified formula, and in practice, there can be additional factors that affect the performance of an air source heat pump, such as the efficiency of the heat pump unit itself and environmental conditions. Additionally, the heat pump may have a coefficient of performance (COP) value that takes into account the actual heat output in relation to the electrical input, providing a more accurate measure of its performance.To get a more precise estimate of heat output, it's advisable to consult the manufacturer's documentation for the specific heat pump model in use, as they may provide more detailed and accurate methods for calculating heat output. Additionally, you may consider using dedicated instrumentation and sensors for better accuracy in measuring temperature and airflow.
Sure, I can provide an example using the formula with an airflow of 0.139 cubic meters per second and a temperature difference of 25 degrees Celsius. Let's use the specific heat of air (Cp) as 1.006 kJ/(kg·°C), which is a commonly accepted value for dry air:Heat Output (Q) = Airflow (Qs) x Specific Heat of Air (Cp) x Temperature Difference (ΔT)Heat Output (Q) = 0.139 m³/s x 1.006 kJ/(kg·°C) x 25°CFirst, let's convert the airflow from cubic meters per second to kilograms per second (since the specific heat value is in kJ/(kg·°C)). You'll need to know the density of air at the given conditions to do this conversion. The density of air at room temperature (around 25°C) and standard atmospheric pressure (1 atm) is approximately 1.184 kg/m³. So:Airflow (Qs) = 0.139 m³/s x 1.184 kg/m³ ≈ 0.165 kg/sNow we can calculate the heat output:Q ≈ 0.165 kg/s x 1.006 kJ/(kg·°C) x 25°C ≈ 4.16 kJ/sSince 1 kJ/s is equivalent to 1 kW (kilowatt), the heat output is approximately 4.16 kW.So, with the given airflow and temperature difference, the estimated heat output of the air source heat pump would be about 4.16 kilowatts.
Om det är rätt så är den copen rätt skitdålig vid +5,
det är ju ändå inte COP som värmer och det är få som har kalibrerade mätdon för att kontrollera tillverkarnas uppgifter som definitivt ät gjorda i labbmiljö. ännu färre som bryr sig.